As given w=z−31iz⇒∣w∣=∣z−31i∣∣z∣=1⇒ distance of z from origin and point (0,31) is same hence z lies on bisector of the line joining points (0,0) and (0,1/3). Hence z lies on a straight line.
If ω= z z- 1 3 i and |ω|=1, then z lies on
JEE Main 2005 — Mathematics Algebra
If ω=z−31iz and ∣ω∣=1, then z lies on
Held on 30 Apr 2005 · Verified 6 Jul 2026.
Options
- A
an ellipse
- B
a circle
- C
a straight line
- D
a parabola.
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