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A real valued function f(x) satisfies the functional equation f(x-y)=f(x) f(y)-f(a-x) f(a+y) where a is a given constant and f(0)=1, f(2 a-x) is…

JEE Main 2005 — Mathematics Algebra

2005mcqmedium

A real valued function f(x)f(x)f(x) satisfies the functional equation f(x−y)=f(x)f(y)−f(a−x)f(x-y)=f(x) f(y)-f(a-x)f(x−y)=f(x)f(y)−f(a−x) f(a+y)f(a+y)f(a+y) where aaa is a given constant and f(0)=1,f(2a−x)f(0)=1, f(2 a-x)f(0)=1,f(2a−x) is equal to

Official previous-year question

Held on 30 Apr 2005 · Verified 6 Jul 2026.

Options

  1. A

    −f(x)-f(x)−f(x)

  2. B

    f(x)f(x)f(x)

  3. C

    f(a)+f(a−x)f(a)+f(a-x)f(a)+f(a−x)

  4. D

    f(−x)f(-x)f(−x)

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