u=a2cos2θ+b2sin2θ+a2sin2θ+b2cos2θ =2a2+b2+2a2−b2cos2θ+2a2+b2+2b2−a2cos2θ ⇒u2=a2+b2+2(2a2+b2)2−(2a2−b2)2cos22θ min value of u2=a2+b2+2ab max value of u2=2(a2+b2) ⇒umax2−umin2=(a−b)2.
If u=√a^2 cos ^2 θ+b^2 sin ^2 θ+√a^2 sin ^2 θ+b^2 cos ^2 θ, then the difference between the maximum and minimum values of u^2 is given by
JEE Main 2004 — Mathematics Algebra
If u=a2cos2θ+b2sin2θ+a2sin2θ+b2cos2θ, then the difference between the maximum and minimum values of u2 is given by
Held on 30 Apr 2004 · Verified 6 Jul 2026.
Options
- A
2(a2+b2)
- B
2a2+b2
- C
(a+b)2
- D
(a−b)2
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