As for given question two cases are possible. (i) Selecting 4 out of first five question and 6 out of remaining 8 question =5C4×8C6=140 choices. (ii) Selecting 5 out of first five question and 5 out of remaining 8 questions =5C5×8C5=56 choices. Therefore, total number of choices =140+56=196.
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of…
JEE Main 2003 — Mathematics Algebra
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
346
- B
140
- C
196
- D
280
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