We have α2=5α−3 ⇒α2−5α+3=0⇒α=25±13. Similarly, β2=5β−3⇒α=25±13∴α=25+13 and β=25−13 or vice - versa α2+β2=450+26=19&αβ=41(25−13)=3 Thus, the equation having βα&αβ as its roots is x2−x(βα+αβ)+αβαβ=0⇒x2−x(αβα2+β2)+1=0 or 3x2−19x+1=0
JEE Main 2002 — Mathematics Algebra
If α=β but α2=5α−3 and β2=5β−3 then the equation having α/β and β/α as its roots is
Held on 30 Apr 2002 · Verified 6 Jul 2026.
3x2−19x+3=0
3x2+19x−3=0
3x2−19x−3=0
x2−5x+3=0
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