Inorganic Chemistry PYQ — Page 29

An acidified manganate solution undergoes disproportionation reaction. The spin-only magnetic moment value of the product having manganese in higher oxidation state is____B.M. (Nearest integer)

Borazine, also known as inorganic benzene, can be prepared by the reaction of $3$-equivalents of "$X$" with $6$-equivalents of "$Y$". "$X$" and "$Y$", respectively are

Element "$E$" belongs to the period $4$ and group $16$ of the periodic table. The valence shell electron configuration of the element, which is just above "$E$" in the group is

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason $R$. Assertion $A$ : Boric acid is a weak acid Reason $R$ : Boric acid is not able to release ${H}^{+}$ ion on its own. It receives ${\mathrm{OH}}^{-}$ ion from water and releases ${H}^{+}$ ion. In the light of the above statements, choose the most appropriate answer from the options given below.

Given below are two statements. One is labelled as Assertion $A$ and the other is labelled as Reason $R$. Assertion $A$ : The first ionization enthalpy for oxygen is lower than that of nitrogen. Reason $R$ : The four electrons in $2p$ orbitals of oxygen experience more electron-electron repulsion. In the light of the above statements, choose the correct answer from the options given below.

The sum of number of lone pairs of electrons present on the central atoms of ${\mathrm{XeO}}_{3},{\mathrm{XeOF}}_{4}$ and ${\mathrm{XeF}}_{6}$ is

Which one of the following elemental forms is not present in the enamel of the teeth?

Number of lone pair $(s)$ of electrons on central atom and the shape of ${\mathrm{BrF}}_{3}$ molecule respectively, are :

The correct order of ionic size of ${N}^{3-},{\mathrm{Na}}^{+},{F}^{-},{\mathrm{Mg}}^{2+}$ and ${O}^{2-}$ is :

The most common oxidation state of Lanthanoid elements is $+3$. Which of the following is likely to deviate easily from $+3$ oxidation state?

The total number of acidic oxides from the following list is: $\mathrm{NO},{N}_{2}O,{B}_{2}{O}_{3},{N}_{2}{O}_{5},\mathrm{CO},{\mathrm{SO}}_{3},{P}_{4}{O}_{10}$

Among the given oxides of nitrogen ; ${N}_{2}O,{N}_{2}{O}_{3},{N}_{2}{O}_{4}$ and ${N}_{2}{O}_{5}$, the number of compound/(s) having $N-N$ bond is

Match List-I with List-II, match the gas evolved during each reaction. <table class="pyq-table"><tbody><tr><td></td><td>List-I</td><td></td><td>List-II</td></tr><tr><td>A</td><td>${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}\overset{\Delta }{\longrightarrow }$</td><td>I</td><td>${H}_{2}$</td></tr><tr><td>B</td><td>${\mathrm{KMnO}}_{4}+\mathrm{HCl}\rightarrow$</td><td>II</td><td>${N}_{2}$</td></tr><tr><td>C</td><td>$\mathrm{Al}+\mathrm{NaOH}+{H}_{2}O\rightarrow$</td><td>III</td><td>${O}_{2}$</td></tr><tr><td>D</td><td>${\mathrm{NaNO}}_{3}\overset{\Delta }{\longrightarrow }$</td><td>IV</td><td>${\mathrm{Cl}}_{2}$</td></tr></tbody></table>Choose the correct answer from the options given below

Amongst the following the number of oxide(s) which are paramagnetic in nature is ${\mathrm{Na}}_{2}O,{\mathrm{KO}}_{2},{\mathrm{NO}}_{2},{N}_{2}O,{\mathrm{ClO}}_{2},\mathrm{NO},{\mathrm{SO}}_{2},{\mathrm{Cl}}_{2}O$

Given below are two statements : Statement I: The pentavalent oxide of group-$15$ element, ${E}_{2}{O}_{5}$, is less acidic than trivalent oxide, ${E}_{2}{O}_{3}$, of the same element. Statement II : The acidic character of trivalent oxide of group $15$ elements, ${E}_{2}{O}_{3}$, decreases down the group. In light of the above statements, choose most appropriate answer from the options given below

Amongst ${\mathrm{FeCl}}_{3}.3{H}_{2}O,{K}_{3}[\mathrm{Fe}{(\mathrm{CN})}_{6}]$ and $[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]{\mathrm{Cl}}_{3}$, the spin-only magnetic moment value of the inner-orbital complex that absorbs light at shortest wavelength is B.M. [nearest integer]

The metal complex that is diamagnetic is (Atomic number : $\mathrm{Fe},26;\mathrm{Cu},29$)

Match List I with List II. <table class="pyq-table"><tbody><tr><td></td><td>List-I (Anion)</td><td></td><td>List-II (gas evolved on reaction with dil. ${H}_{2}{\mathrm{SO}}_{4}$)</td></tr><tr><td>(A)</td><td>${\mathrm{CO}}_{3}^{2-}$</td><td>(I)</td><td>Colourless gas which turns lead acetate paper black.</td></tr><tr><td>(B)</td><td>${S}^{2-}$</td><td>(II)</td><td>Colourless gas which turns acidified potassium dichromate solution green.</td></tr><tr><td>(C)</td><td>${\mathrm{SO}}_{3}^{2-}$</td><td>(III)</td><td>Brown fumes which turns acidified KI solution containing starch blue.</td></tr><tr><td>(D)</td><td>${\mathrm{NO}}_{2}^{-}$</td><td>(IV)</td><td>Colourless gas evolved with brisk effervescence, which turns lime water milky.</td></tr></tbody></table>Choose the correct answer from the options given below

The IUPAC nomenclature of an element with electronic configuration $[\mathrm{Rn}]5{f}^{14}6{d}^{1}7{s}^{2}$ is

Given below are two statements: Statement I : The chlorides of $\mathrm{Be}$ and $\mathrm{Al}$ have Cl-bridged structure. Both are soluble in organic solvents and act as Lewis bases. Statement II: Hydroxides of $\mathrm{Be}$ and $\mathrm{Al}$ dissolve in excess alkali to give beryllate and aluminate ions. In the light of the above statements. Choose the correct answer from the options given below.

${\mathrm{PCl}}_{5}$ is well known but ${\mathrm{NCl}}_{5}$ is not.Because,

Match List - I with List - II <table class="pyq-table"><tbody><tr><td></td><td>List-II</td><td></td><td>List-II</td></tr><tr><td>A</td><td>${N}_{2}(g)+3{H}_{2}(g)\rightarrow 2{\mathrm{NH}}_{3}(g)$</td><td>I</td><td>$\mathrm{Cu}$</td></tr><tr><td>B</td><td>$\mathrm{CO}(g)+3{H}_{2}(g)\rightarrow {\mathrm{CH}}_{4}(g)+{H}_{2}O(g)$</td><td>II</td><td>$\mathrm{Cu}/\mathrm{ZnO}-{\mathrm{Cr}}_{2}{O}_{3}$</td></tr><tr><td>C</td><td>$\mathrm{CO}(g)+{H}_{2}(g)\rightarrow \mathrm{HCHO}(g)$</td><td>III</td><td>${\mathrm{Fe}}_{x}{O}_{y}+{K}_{2}O+{\mathrm{Al}}_{2}{O}_{3}$</td></tr><tr><td>D</td><td>$\mathrm{CO}(g)+2{H}_{2}(g)\rightarrow {\mathrm{CH}}_{3}\mathrm{OH}(g)$</td><td>IV</td><td>$\mathrm{Ni}$</td></tr></tbody></table>Choose the correct answer from the options given below

Given below are the oxides : ${\mathrm{Na}}_{2}O,{\mathrm{As}}_{2}{O}_{3},{N}_{2}O,\mathrm{NO}$ and ${\mathrm{Cl}}_{2}{O}_{7}$ Number of amphoteric oxides is :

The coordination number of central metal ion in [Fe(CN)₆]⁴⁻ is: