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The solution of the differential equation dy dx = x+y x-y is

CUET UG 2025 — Mathematics Calculus

2025mcqmedium

The solution of the differential equation dydx=x+yx−y\frac{dy}{dx} = \frac{x+y}{x-y}dxdy​=x−yx+y​ is

Official previous-year question

Held on 2 Jun 2025 · Verified 13 Jul 2026.

Options

  1. A

    y=x2log⁡e(x2+y2)+Cy = \frac{x}{2}\log_e(x^2 + y^2) + Cy=2x​loge​(x2+y2)+C : C is an arbitary constant

  2. B

    y=x2+y2+Cy = \sqrt{x^2 + y^2} + Cy=x2+y2​+C : C is an arbitrary constant

  3. C

    y=12log⁡e(x2+y2)+cy = \frac{1}{2}\log_e(x^2 + y^2) + cy=21​loge​(x2+y2)+c : C is an arbitrary constant

  4. D

    tan⁡−1yx=12log⁡e(x2+y2)+C\tan^{-1}\frac{y}{x} = \frac{1}{2}\log_e(x^2 + y^2) + Ctan−1xy​=21​loge​(x2+y2)+C: C is an arbitrary constant

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