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Let y = cos(sin x^2), then the value of dy dx at x = √π 2 is equal to

CUET UG 2025 — Mathematics Calculus

2025mcqmedium

Let y=cos⁡(sin⁡x2)y = \cos(\sin x^2)y=cos(sinx2), then the value of dydx\frac{dy}{dx}dxdy​ at x=π2x = \frac{\sqrt{\pi}}{2}x=2π​​ is equal to

Official previous-year question

Held on 30 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    −π2sin⁡(12)-\sqrt{\frac{\pi}{2}}\sin\left(\frac{1}{\sqrt{2}}\right)−2π​​sin(2​1​)

  2. B

    −π2sin⁡(12)-\frac{\sqrt{\pi}}{2}\sin\left(\frac{1}{\sqrt{2}}\right)−2π​​sin(2​1​)

  3. C

    −π2cos⁡(12)-\sqrt{\frac{\pi}{2}}\cos\left(\frac{1}{\sqrt{2}}\right)−2π​​cos(2​1​)

  4. D

    π2cos⁡(12)\sqrt{\frac{\pi}{2}}\cos\left(\frac{1}{\sqrt{2}}\right)2π​​cos(2​1​)

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