CUET UG 2025 — Mathematics Calculus
Let f(x)=⎩⎨⎧x∣x∣,1,x=0x=0 and g(x)=⎩⎨⎧xsin(x1),0,x=0x=0
Then at the origin, which one of the following is true?
Held on 13 May 2025 · Verified 13 Jul 2026.
f(x) is continuous, but g(x) is not continuous
g(x) is continuous, but f(x) is not continuous
Both f(x) and g(x) are continuous
Neither f(x) nor g(x) is continuous
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
The derivative of x³ + 2x² - 5x + 1 is:
If the function $f(x) = 2x^3 + 9x^2 + 12x-1$ is given,then $f(x)$ have
If $\int \frac{dx}{(x-1)^3/^4. (x+2)^5/^4} = a[1 - g(x)]^b + c$, where $c$ is a constant of integration, then which of the following are true? (A) $a = \frac{2}{3}$ (B) $\beta = \frac{3}{4}$ (C) $3\alpha + 4\beta = 5$ (D) $g(x) = \frac{3}{(x+2)}$ Choose the **correct** answer from the options given below:
Match **List-I** with **List-II** | List-I | List-II | |---|---| | **Function** | **Increasing on the interval** | | (A) $f(x) = -x^2 - 2x + 1$ | (I) $(-\infty, -1)$ | | (B) $f(x) = x^2 + 1$ | (II) $(1, \infty)$ | | (C) $f(x) = x^2 - 2x + 3$ | (III) $(-\infty, 0)$ | | (D) $f(x) = -x^2$ | (IV) $(0, \infty)$ | Choose the correct answer from the options given below:
The integral $\int e^x\left(\frac{x-1}{2x^2}\right)dx$ is equal to
Work through every CUET UG Calculus PYQ, year by year.