Skip to main content

Let f(x)= … and g(x)= … Then at the origin, which one of the following is true?

CUET UG 2025 — Mathematics Calculus

2025mcqmedium

Let f(x)={∣x∣x,x≠01,x=0f(x)=\begin{cases}\dfrac{|x|}{x},&x\ne0\\1,&x=0\end{cases}f(x)=⎩⎨⎧​x∣x∣​,1,​x=0x=0​ and g(x)={xsin⁡(1x),x≠00,x=0g(x)=\begin{cases}x\sin\left(\dfrac{1}{x}\right),&x\ne0\\0,&x=0\end{cases}g(x)=⎩⎨⎧​xsin(x1​),0,​x=0x=0​

Then at the origin, which one of the following is true?

Official previous-year question

Held on 13 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    f(x)f(x)f(x) is continuous, but g(x)g(x)g(x) is not continuous

  2. B

    g(x)g(x)g(x) is continuous, but f(x)f(x)f(x) is not continuous

  3. C

    Both f(x)f(x)f(x) and g(x)g(x)g(x) are continuous

  4. D

    Neither f(x)f(x)f(x) nor g(x)g(x)g(x) is continuous

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

CUET UG Calculus in other years

More CUET UG Calculus questions

Other Mathematics topics for CUET UG

Keep practicing Calculus

Work through every CUET UG Calculus PYQ, year by year.

Browse all Mathematics topics