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If x = asec^3 θ, y = a tan^3 θ, then d^2y dx^2 equals.

CUET UG 2025 — Mathematics Calculus

2025mcqmedium

If x=asec⁡3θx = a\sec^3 \thetax=asec3θ, y=atan⁡3θy = a \tan^3 \thetay=atan3θ, then d2ydx2\frac{d^2y}{dx^2}dx2d2y​ equals.

Official previous-year question

Held on 27 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    cos⁡5θ3asin⁡θ\frac{\cos^5 \theta}{3a\sin \theta}3asinθcos5θ​

  2. B

    3acos⁡5θsin⁡θ\frac{3a\cos^5 \theta}{\sin \theta}sinθ3acos5θ​

  3. C

    sin⁡5θ3acos⁡θ\frac{\sin^5 \theta}{3a\cos \theta}3acosθsin5θ​

  4. D

    3asin⁡5θcos⁡θ\frac{3a\sin^5 \theta}{\cos \theta}cosθ3asin5θ​

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