Skip to main content

Particular solution of the differential equation log ( dy dx ) = x + y, given that when x = 0, y = 0 is:

CUET UG 2023 — Mathematics Calculus

2023mcqmedium

Particular solution of the differential equation log⁡(dydx)=x+y\log\left(\frac{dy}{dx}\right) = x + ylog(dxdy​)=x+y, given that when x=0,y=0x = 0, y = 0x=0,y=0 is:

Official previous-year question

Held on 25 May 2023 · Verified 13 Jul 2026.

Options

  1. A

    ex+e−y=2e^x + e^{-y} = 2ex+e−y=2

  2. B

    e−x+ey=2e^{-x} + e^y = 2e−x+ey=2

  3. C

    ex+ey=2e^x + e^y = 2ex+ey=2

  4. D

    e−x+e−y=2e^{-x} + e^{-y} = 2e−x+e−y=2

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

CUET UG Calculus in other years

More CUET UG Calculus questions

Other Mathematics topics for CUET UG

Keep practicing Calculus

Work through every CUET UG Calculus PYQ, year by year.

Browse all Mathematics topics