ax=t−t1 and by=t+t1. So (by)2−(ax)2=4. Differentiating: b22ydxdy−a22x=0, giving dxdy=a2yb2x.
CUET UG 2023 — Mathematics Calculus
∫(x+x1)2dx equals :
Held on 30 May 2023 · Verified 13 Jul 2026.
3x3+x1−2x+c
3x3−x1+2x+c
3x3−x1−2x+c
3x3+x1+2x+c
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