Partial fractions: (x2+3)(x2+5)x2+4=x2+3A+x2+5B.
Solving: A+B=1 and 5A+3B=4, giving A=B=1/2.
Integrating: u=231, v=251.
u21+v21=12+20=32.
∫ x^2 + 4 (x^2 + 3)(x^2 + 5) dx = u tan^-1 ( x √3 ) + v tan^-1 ( x √5 ) + c, where c is arbitrary constant, then value of 1 u^2 + 1 v^2 is equal to :
CUET UG 2022 — Mathematics Calculus
∫(x2+3)(x2+5)x2+4dx=utan−1(3x)+vtan−1(5x)+c, where c is arbitrary constant, then value of u21+v21 is equal to :
Held on 7 Aug 2022 · Verified 13 Jul 2026.
Options
- A
32
- B
16
- C
08
- D
04
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