(x+1)dxdy=1+y is separable.
1+ydy=x+1dx
Integrating: ln(1+y)=ln(x+1)+lnC, so x+11+y=C, equivalently y+1x+1=C.
The solution of the differential equation (x+1) dy dx = 1 + y is
CUET UG 2022 — Mathematics Calculus
2022mcqeasy
The solution of the differential equation (x+1)dxdy=1+y is
Official previous-year question
Held on 30 Aug 2022 · Verified 13 Jul 2026.
Options
- A
1+x21+y+y2=C
- B
log(x+1)−log(y+21)=C
- C
y+1x+1=C
- D
log(1+y)−23log(x+1)=C
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