Expand: (1+x2)2(1−x)2=(1+x2)21−2x+x2=(1+x2)21+x2−(1+x2)22x=1+x21−(1+x2)22x. Let f(x)=1+x21, then f′(x)=−(1+x2)22x. Using ∫ex[f(x)+f′(x)]dx=exf(x)+C, the answer is 1+x2ex+C.
∫ e^x ( 1-x 1+x^2 )^2 dx =
CUET UG 2022 — Mathematics Calculus
∫ex(1+x21−x)2dx=
Held on 10 Aug 2022 · Verified 13 Jul 2026.
Options
- A
1+x2ex+C
- B
1+x2−ex+C
- C
(1+x2)2ex+C
- D
(1+x2)2−ex+C
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
CUET UG Calculus in other years
More CUET UG Calculus questions
The derivative of x³ + 2x² - 5x + 1 is:
The value of the definite integral $I = \int_{1}^{2} \frac{1}{x(1 + x^2)}dx$ is:
If $y = ax^2 + bx$ has minima at $x = 2$ and the minimum value is -12, then which of the following are correct? (A) $a = 3$ (B) $a = -3$ (C) $b = 12$ (D) $b = -12$ Choose the correct answer from the options given below:
A balloon which always remains spherical, has a variable diameter $\frac{3}{2}(5x+7)$. Then the rate of change of its volume with respect to x is
Match List-I with List-II | List-I | List-II | |---|---| | **Differential equation** | **Degree** | | (A) $\frac{d^2y}{dx^2} + \sqrt{\frac{dy}{dx}} - y = 0$ | (I) 6 | | (B) $\sqrt{\frac{d^3y}{dx^3}} - \sqrt[12]{\frac{d^2y}{dx^2}} = 0$ | (II) Not defined | | (C) $\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} + e^{\frac{dx}{dx}} = x^2$ | (III) 3 | | (D) $\sqrt[3]{\frac{dy}{dx}} - \frac{d^2y}{dx^2} = e^x$ | (IV) 2 | Choose the correct answer from the options given below:
Other Mathematics topics for CUET UG
Keep practicing Calculus
Work through every CUET UG Calculus PYQ, year by year.