Integrating: f(x)=x5+x41+C.
Using f(1)=0: 1+1+C=0⇒C=−2.
So f(x)=x5+x41−2.
f(2)=32+161−2=30+161.
f(1/2)=321+16−2=14+321.
f(2)−2f(1/2)=30+161−28−161=2.
If d dx(f(x)) = 5x^4 - 4 x^5 such that f(1) = 0. Then f(2) - 2f ( 1 2 ) is equal to :
CUET UG 2022 — Mathematics Calculus
If dxd(f(x))=5x4−x54 such that f(1)=0. Then f(2)−2f(21) is equal to :
Held on 7 Aug 2022 · Verified 13 Jul 2026.
Options
- A
−2
- B
2
- C
0
- D
1
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