f(x)=x2 for x≥0, −x2 for x<0. f′(x)=2x for x>0, −2x for x<0. Both give 0 at x=0, so (A) differentiable: TRUE.
(B) False since f IS differentiable at 0.
(C) f′′ changes sign at 0 (from −2 to 2), so point of inflection: TRUE.
(D) f(−x)=−f(x) (odd function), symmetric about origin not y-axis: FALSE.
So (A) and (C) only.
Note: 'point of infection' in the question is interpreted as 'point of inflection'.
Consider the following statements for the curve f(x) = x|x| and find that which of the following(s) are/is correct : (A) f(x) = x|x| is…
CUET UG 2022 — Mathematics Calculus
Consider the following statements for the curve f(x)=x∣x∣ and find that which of the following(s) are/is correct :
(A) f(x)=x∣x∣ is differentiable at x=0.
(B) f(x)=x∣x∣ is continuous at x=0 but not differentiable at x=0.
(C) f(x)=x∣x∣ has point of infection at x=0.
(D) f(x)=x∣x∣ is symmetrical about y-axis.
Choose the correct answer from the options given below :
Held on 7 Aug 2022 · Verified 13 Jul 2026.
Options
- A
(A) and (C) only
- B
(B) and (D) only
- C
(B) only
- D
(A), (B) and (D) only
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