f(x)=x2 for x≥0, −x2 for x<0. f′(x)=2x for x>0, −2x for x<0. Both give 0 at x=0, so (A) differentiable: TRUE.
(B) False since f IS differentiable at 0.
(C) f′′ changes sign at 0 (from −2 to 2), so point of inflection: TRUE.
(D) f(−x)=−f(x) (odd function), symmetric about origin not y-axis: FALSE.
So (A) and (C) only.
Note: 'point of infection' in the question is interpreted as 'point of inflection'.