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The probability distribution function of a normal variate with mean μ and variance σ^2 is given by: f(x) = 1 σ√2πe^- 1 2( x-μ σ)^2, -∞ < x < ∞, -∞ <…

CUET UG 2025 — Mathematics Algebra

2025mcqmedium

The probability distribution function of a normal variate with mean μ\muμ and variance σ2\sigma^2σ2 is given by:

f(x)=1σ2πe−12(x−μσ)2f(x) = \frac{1}{\sigma\sqrt{2\pi}}e^{-\frac{1}{2}(\frac{x-\mu}{\sigma})^2}f(x)=σ2π​1​e−21​(σx−μ​)2, −∞<x<∞-\infty < x < \infty−∞<x<∞, −∞<μ<∞-\infty < \mu < \infty−∞<μ<∞, σ>0\sigma > 0σ>0

If y=f(x)y = f(x)y=f(x) be the normal probability curve, then which of the following is correct?

(A) The normal curve is symmetrical about the line x=μx = \mux=μ.

(B) Mean, median and mode of the distribution coincide.

(C) Y- axis is an asymptote to the normal curve.

(D) If x increases numerically, f(x)f(x)f(x) decreases rapidly.

Choose the correct answer from the options given below:

Official previous-year question

Held on 21 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    (A) and (D) only

  2. B

    (A), (B) and (D) only

  3. C

    (A), (B), (C) and (D)

  4. D

    (B) and (C) only

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