The feasible region associated with the inequality 2x + 3y > 4 is

The inequality $2x + 3y > 4$2x+3y>4 uses a strict inequality (>), not a non-strict inequality (≥).

A strict inequality represents an open half plane where the boundary line is not included.

This eliminates options with "closed" half plane.

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To determine which side of the line the feasible region lies on, test the origin $(0, 0)$(0,0).

Substitute $x = 0$x=0 and $y = 0$y=0 into $2x + 3y > 4$2x+3y>4:

$$2(0) + 3(0) > 4$$2(0)+3(0)>4

$$0 > 4$$0>4

This is false, so the origin does not satisfy the inequality.

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The origin is not in the feasible region. Therefore, the feasible region is on the opposite side of the boundary line from the origin.

The feasible region is an open half plane not containing the origin.