a=i^+2j^+3k^,b=−i^+2j^+k^,c=3i^+j^
Since (a+λb)⊥c, their dot product equals zero:
(a+λb)⋅c=0
a+λb=(i^+2j^+3k^)+λ(−i^+2j^+k^)
=(1−λ)i^+(2+2λ)j^+(3+λ)k^
Taking the dot product with c=3i^+j^+0k^:
(a+λb)⋅c=3(1−λ)+1(2+2λ)+0(3+λ)
=3−3λ+2+2λ
=5−λ
5−λ=0
λ=5
Therefore, λ=5