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Let A = [a_ij]_n × n be a matrix. Then Match List-I with List-II | List-I | List-II | | --- | --- | | (A) A^T = A | (I) A is a singular matrix | |…

CUET UG 2025 — Mathematics Algebra

2025mcqeasy

Let A = [aij]n×n[a_{ij}]_{n \times n}[aij​]n×n​ be a matrix. Then

Match List-I with List-II

List-I List-II
(A) AT=AA^T = AAT=A (I) A is a singular matrix
(B) AT=−AA^T = -AAT=−A (II) A is a non-singular matrix
(C) ∣A∣=0\vert A\vert = 0∣A∣=0 (III) A is a skew symmetric matrix
(D) ∣A∣≠0\vert A\vert \neq 0∣A∣=0 (IV) A is a symmetric matrix

Choose the correct answer from the options given below:

Official previous-year question

Held on 14 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

  2. B

    (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

  3. C

    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

  4. D

    (A) - (I), (B) - (II), (C) - (IV), (D) - (III)

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