Given matrix A=a00aa0aaa
For any n×n matrix A, the relationship between the determinant of the adjoint and the determinant of A is:
∣adjA∣=∣A∣n−1
Since the given matrix is 3×3, we have n=3:
∣adjA∣=∣A∣3−1
∣adjA∣=∣A∣2
The matrix A is upper triangular (all entries below the main diagonal are zero).
For an upper triangular matrix, the determinant equals the product of the diagonal elements:
∣A∣=a×a×a
∣A∣=a3
Using the formula:
∣adjA∣=∣A∣2
∣adjA∣=(a3)2
∣adjA∣=a6
Therefore, ∣adjA∣=a6