For a skew symmetric matrix, two properties hold:
- All diagonal elements are zero: aii=0
- Elements satisfy: aij=−aji
Given matrix:
x−2y230z−2−40
The diagonal elements are (x−2), 0, and 0.
Since all diagonal elements must be zero:
x−2=0
x=2
For elements at position (1,2) and (2,1):
Element at (1,2) =3
Element at (2,1) =y
These must be negatives of each other:
3=−y
y=−3
For elements at position (2,3) and (3,2):
Element at (2,3) =−4
Element at (3,2) =z
These must be negatives of each other:
−4=−z
z=4
x+y+z=2+(−3)+4
x+y+z=3
Therefore, the value of x+y+z is 3.