(A−AT)T=AT−(AT)T
=AT−A
=−(A−AT)
Since the transpose equals the negative of itself, A−AT is skew-symmetric.
(A)→(II)
(AAT)T=(AT)T⋅AT
=A⋅AT
=AAT
Since the transpose equals itself, AAT is symmetric.
(B)→(III)
Since A⋅A−1=I, taking determinant on both sides:
det(A)⋅det(A−1)=det(I)=1
det(A−1)=det(A)1
=[det(A)]−1
(C)→(IV)
From the standard identity:
A−1=det(A)adj(A)
adj(A)=det(A)⋅A−1
=∣A∣A−1
(D)→(I)
| List-I |
List-II |
| (A) A−AT |
(II) Skew-symmetric |
| (B) AAT |
(III) Symmetric |
| (C) det(A−1) |
(IV) [det(A)]−1 |
| (D) adj(A) |
(I) ∥A∥A−1 |