Given that A is a square matrix of order 3 and ∣A∣=2.
For a matrix of order n, when multiplying by a constant k:
∣kA∣=kn×∣A∣
Here, k=2 and n=3:
∣2A∣=23×∣A∣
∣2A∣=8×2
∣2A∣=16
For any square matrix B of order n:
∣adj(B)∣=∣B∣n−1
Let B=2A, where ∣2A∣=16 and n=3:
∣adj(2A)∣=∣2A∣3−1
∣adj(2A)∣=∣2A∣2
∣adj(2A)∣=(16)2
∣adj(2A)∣=256
Therefore, ∣adj(2A)∣=256.