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A furniture trader deals in only two items - chairs and tables. He has Rs. 50,000 to invest and a space to store almost 35 items. A chair costs him…

CUET UG 2025 — Mathematics Algebra

2025mcqmedium

A furniture trader deals in only two items - chairs and tables. He has Rs. 50,000 to invest and a space to store almost 35 items. A chair costs him Rs. 1000 and a table costs him Rs. 2000. The trader earns a profit of Rs. 150 and Rs. 250 on a chair and a table, respectively. Choose the correct option among following that describes the given linear programming problem (LPP) to maximize the profit ( where x and y are the number of chairs and tables that trader buys and sells)?

Official previous-year question

Held on 19 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    Maximize z=150x+250yz = 150x + 250yz=150x+250y;
    Subjected to constants,
    x+y≤35,x+2y≥50,x≥0,y≥0x + y \leq 35, x + 2y \geq 50, x \geq 0, y \geq 0x+y≤35,x+2y≥50,x≥0,y≥0

  2. B

    Maximize z=150x+250yz = 150x + 250yz=150x+250y;
    Subjected to constants,
    x+y≤35,x+2y≤50,x≥0,y≥0x + y \leq 35, x + 2y \leq 50, x \geq 0, y \geq 0x+y≤35,x+2y≤50,x≥0,y≥0

  3. C

    Maximize z=150x+250yz = 150x + 250yz=150x+250y;
    Subjected to constants,
    x+y≥35,2x+y≤50,x≥0,y≥0x + y \geq 35, 2x + y \leq 50, x \geq 0, y \geq 0x+y≥35,2x+y≤50,x≥0,y≥0

  4. D

    Maximize z=150x+250yz = 150x + 250yz=150x+250y;
    Subjected to constants,
    x+y≥35,2x+y≥50,x≥0,y≥0x + y \geq 35, 2x + y \geq 50, x \geq 0, y \geq 0x+y≥35,2x+y≥50,x≥0,y≥0

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