Let X be the number of kings. P(X=0)=(248)/(252)=188/221, P(X=1)=32/221, P(X=2)=1/221. Then E(X)=34/221 and E(X2)=36/221. Variance =E(X2)−[E(X)]2=36/221−1156/(221)2=(7956−1156)/(221)2=6800/(221)2.
Two cards are drawn simultaneously from a well shuffled pack of 52 cards. Then variance of the number of kings is
CUET UG 2023 — Mathematics Algebra
2023mcqhard
Two cards are drawn simultaneously from a well shuffled pack of 52 cards. Then variance of the number of kings is
Official previous-year question
Held on 23 May 2023 · Verified 13 Jul 2026.
Options
- A
(221)2680
- B
(221)26080
- C
221680
- D
(221)26800
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