Sum of probabilities: 5k+2k+3k=10k=1, so k=0.1. E(X)=0(0.5)+1(0.2)+2(0.3)=0.2+0.6=0.8.
The random variable X has a probability distribution
P(X=x)=⎩⎨⎧5k,2k,3k,0,x=0x=1x=2otherwise.
Then, the value of E(X) is :
Held on 17 Aug 2022 · Verified 13 Jul 2026.
0.8
0.4
1
0.5
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