Probability of a doublet in one throw of two dice: p=366=61.
Using binomial distribution with n=3:
P(X=k)=(k3)(61)k(65)3−k.
P(0)=216125, P(1)=21675, P(2)=21615, P(3)=2161.
The probability distribution of number of doublets in three throws of a pair of dice is
Held on 30 Aug 2022 · Verified 13 Jul 2026.
| x | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| P(X=x) | 125/216 | 75/216 | 15/216 | 1/216 |
| x | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| P(X=x) | 75/216 | 125/216 | 1/216 | 15/216 |
| x | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| P(X=x) | 1/216 | 75/216 | 15/216 | 125/216 |
| x | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| P(X=x) | 1/216 | 15/216 | 75/216 | 125/216 |
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