Probability of a doublet in one throw of two dice: p=366=61.
Using binomial distribution with n=3:
P(X=k)=(k3)(61)k(65)3−k.
P(0)=216125, P(1)=21675, P(2)=21615, P(3)=2161.
The probability distribution of number of doublets in three throws of a pair of dice is
CUET UG 2022 — Mathematics Algebra
2022mcqeasy
The probability distribution of number of doublets in three throws of a pair of dice is
Official previous-year question
Held on 30 Aug 2022 · Verified 13 Jul 2026.
Options
- A
x 0 1 2 3 P(X=x) 125/216 75/216 15/216 1/216 - B
x 0 1 2 3 P(X=x) 75/216 125/216 1/216 15/216 - C
x 0 1 2 3 P(X=x) 1/216 75/216 15/216 125/216 - D
x 0 1 2 3 P(X=x) 1/216 15/216 75/216 125/216
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