Singular ⇒ determinant =0.
4sin2x−3=0⇒sin2x=43⇒sinx=23 (since sinx>0 on (0,π)).
So x=3π or 32π.
If 0<x<π and the matrix [4sinx−3−1sinx] is singular, then the values of x are :
Held on 30 Aug 2022 · Verified 13 Jul 2026.
3π,32π
6π,65π
6π,3π
6π,32π
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