P(B1)=P(B2)=1/2. P(Black∣B1)=5/9, P(Black∣B2)=6/11. By Bayes' theorem: P(B2∣Black)=(1/2)(5/9)+(1/2)(6/11)(1/2)(6/11)=5/9+6/116/11=109/996/11=11×1096×99=10954.
Bag I contains 4 red and 5 black balls, while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and…
CUET UG 2022 — Mathematics Algebra
Bag I contains 4 red and 5 black balls, while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be black. Then the probability that it was drawn from Bag II, is
Held on 10 Aug 2022 · Verified 13 Jul 2026.
Options
- A
10954
- B
10951
- C
10964
- D
11954
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