Given OP=a and OQ=b.
Since OP=5OR, we have OR=5a.
Also, OQ=5RM, which gives RM=5b.
The position vector of M is given by OM=OR+RM=5a+5b.
Now, we need to find PM:
PM=OM−OP
PM=(5a+5b)−a
PM=5b−4a=51(b−4a)
Answer: 51(b−4a)
JEE Main 2026 — Mathematics Vectors & 3D Geometry
Let O be the origin, OP=a and OQ=b. If R is the point on OP such that OP=5OR, and M is the point such that OQ=5RM, then PM is equal to :
Held on 5 Apr 2026 · Verified 6 Jul 2026.
51(a−4b)
51(b−4a)
51(−a+4b)
51(−b+4a)
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