a×b=2(a×c)⇒a×(b−2c)=0, so b−2c=ka.
b⋅c=4⋅2⋅cos60°=4.
Dot with c: 4=2(4)+k(a⋅c)⇒k(a⋅c)=−4.
Dot with a: a⋅b=2(a⋅c)+k.
Dot with b: 16=8+ka⋅b=8+k(−k8+k)=k2⇒k=±4.
a⋅c=−k4=∓1⇒∣a⋅c∣=1.
JEE Main 2026 — Mathematics Vectors & 3D Geometry
Let a,b,c be three vectors such that a×b=2(a×c). If ∣a∣=1,∣b∣=4,∣c∣=2, and the angle between b and c is 60∘, then ∣a⋅c∣ is equal to
Held on 23 Jan 2026 · Verified 6 Jul 2026.
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