Given,
r×b+b×c=0
⇒r×b−c×b=0
⇒(r−c)×b=0
⇒(r−c)∣∣b
Therefore, r−c=λb
⇒r=c+λb
Also,
r⋅a=0 (given)
⇒(c+λb)⋅a=0
⇒c⋅a+λb⋅a=0
⇒λ=b⋅a−c⋅a
Now,
r⋅c=(c+λb)⋅c
=(c−b⋅ac⋅ab)⋅c
=∣c∣2−(b⋅ac⋅a)(b⋅c)
=74−(315)×8
=74−40=34
JEE Main 2023 — Mathematics Vectors & 3D Geometry
If a=i^+2k^,b=i^+j^+k^,c=7i^−3j^+4k^,r×b+b×c=0 and r⋅a=0 then r.c is equal to:
Held on 29 Jan 2023 · Verified 6 Jul 2026.
34
12
36
30
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