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Let a, b and be three unit vectors such that | a- b|^2+| a- |^2=8. Then | a+2 b|^2+| a+2 |^2 is equal to

JEE Main 2020 — Mathematics Vectors & 3D Geometry

2020integermedium

Let a⃗,b⃗\vec{a},\vec{b}a,b and c⃗\vec{c}c be three unit vectors such that ∣a⃗−b⃗∣2+∣a⃗−c⃗∣2=8{|\vec{a}-\vec{b}|}^{2}+{|\vec{a}-\vec{c}|}^{2}=8∣a−b∣2+∣a−c∣2=8. Then ∣a⃗+2b⃗∣2+∣a⃗+2c⃗∣2{|\vec{a}+2\vec{b}|}^{2}+{|\vec{a}+2\vec{c}|}^{2}∣a+2b∣2+∣a+2c∣2 is equal to

Official previous-year question

Held on 2 Sept 2020 · Verified 6 Jul 2026.

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