Given,
a×(b×c)=23(b+c)
⇒(a⋅c)b−(a⋅b)c=23b+23c
On comparing, we get
−(a⋅b)=23
⇒(a⋅b)=−23
⇒∣a∣∣b∣cosθ=−23
Given a,b are unit vector,
∣a∣=∣b∣=1
From equation (i)
cosθ=−23
⇒cosθ=cos65π
⇒θ=65π
JEE Main 2016 — Mathematics Vectors & 3D Geometry
Let a,b and c be three unit vectors such that a×(b×c)=23(b+c). If b is not parallel to c , then the angle between a and b is
Held on 3 Apr 2016 · Verified 6 Jul 2026.
32π
65π
43π
2π
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