x2−x1l1l2y2−y1 m1 m2z2−z1n1n2=0 11k−112−1−k1=0⇒02k+201+k1−1−k1=0 k2+3k2=0⇒k(k+3)=0 or k=0 or −3
The lines x-2 1= y-3 1= z-4 - k and x-1 k= y-4 1= z-5 1 are coplanar if
JEE Main 2003 — Mathematics Vectors & 3D Geometry
The lines 1x−2=1y−3=−kz−4 and kx−1=1y−4=1z−5 are coplanar if
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
k=3 or −2
- B
k=0 or −1
- C
k=1 or −1
- D
k=0 or −3
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