a+b+c=0⇒b+c=−a⇒(b+c)2=(a)2=52+32+2bc=72 ⇒2∣b∣∣c∣cosθ=49−34=15⇒2×5×3cosθ=15⇒cosθ=1/2⇒θ=3π=60∘
If a, b, are vectors such that a+ b+ =0 and | a|=7,| b|=5,| |=3 then angle between vector b and is
JEE Main 2002 — Mathematics Vectors & 3D Geometry
If a,b,c are vectors such that a+b+c=0 and ∣a∣=7,∣b∣=5,∣c∣=3 then angle between vector b and c is
Held on 30 Apr 2002 · Verified 6 Jul 2026.
Options
- A
60∘
- B
30∘
- C
45∘
- D
90∘
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