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The number of solutions of tan^-1 4x + tan^-1 6x = π 6, where - 1 2√6 < x < 1 2√6, is equal to

JEE Main 2026 — Mathematics Trigonometry

2026mcqmedium

The number of solutions of tan⁡−14x+tan⁡−16x=π6\tan^{-1} 4x + \tan^{-1} 6x = \frac{\pi}{6}tan−14x+tan−16x=6π​, where −126<x<126-\frac{1}{2\sqrt{6}} < x < \frac{1}{2\sqrt{6}}−26​1​<x<26​1​, is equal to

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    3

  2. B

    0

  3. C

    2

  4. D

    1

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