cosecθ=232(3−1)±4(3+1−23)+163=232(3−1)±16+83=232(3−1)±(2+23)
cosecθ=2 or 3−2
∴sinθ=21 or 2−3
∴sinθ=21 has 3 solutions & also sinθ=2−3
has 3 solutions in [6−7π,34π]
JEE Main 2025 — Mathematics Trigonometry
If θ∈[−67π,34π], then the number of solutions of 3cosec2θ−2(3−1)cosecθ−4=0, is equal to
Held on 2 Apr 2025 · Verified 6 Jul 2026.
6
8
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7
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