5(45+1)−3(45−1)43(5+1)+5(45−1)=25+885−2=5+445−1×5−45−4 =−1120−165−5+4=11175−24⇒a=17,b=27,c=11a+b+c=52
If the value of 5cos36∘−3sin18∘3cos36∘+5sin18∘ is ca5−b, where a,b,c are natural numbers and gcd(a,c)=1, then a+b+c is equal to :
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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