Given that sin−1x=2tan−1x
⇒sin−1x=sin−1(1+x22x)
⇒x=(1+x22x)
⇒x+x3=2x
⇒x3−x=0
⇒x(x2−1)=0
⇒x=0,−1,1.
But x∈(−1,1], so the number of roots are 2, x=0&1
JEE Main 2023 — Mathematics Trigonometry
For x∈(−1,1], the number of solutions of the equation sin−1x=2tan−1x is equal to
Held on 13 Apr 2023 · Verified 6 Jul 2026.
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