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The number of solutions of sin 3 x=cos 2 x, in the interval ( π 2, π ) is

JEE Main 2018 — Mathematics Trigonometry

2018mcqmedium

The number of solutions of sin⁡3x=cos⁡2x\sin 3 x=\cos 2 xsin3x=cos2x, in the interval (π2,π)\left(\frac{\pi}{2}, \pi\right)(2π​,π) is

Official previous-year question

Held on 15 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    3

  2. B

    4

  3. C

    2

  4. D

    1

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