sin[cot][−1(1+x)]=cos(tan)(−1x)

Let, cotλ=1+x
tanβ=x
⇒sinλ=cosβ
⇒x2+2x+21=11+x21
⇒x2+2x+2=x2+1
⇒x=−1/2
JEE Main 2017 — Mathematics Trigonometry
A value of x satisfying the equation sin[cot−1(1+x)]=cos[tan−1x], is:
Held on 9 Apr 2017 · Verified 6 Jul 2026.
−21
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−1
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