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The expression tanA 1- cotA+ cotA 1- tanA can be written as :

JEE Main 2013 — Mathematics Trigonometry

2013mcqeasy

The expression tanA1−cotA+cotA1−tanA\frac{\mathrm{tanA}}{1-\mathrm{cotA}}+\frac{\mathrm{cotA}}{1-\mathrm{tanA}}1−cotAtanA​+1−tanAcotA​ can be written as :

Official previous-year question

Held on 7 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    tanA+cotA\mathrm{tanA}+\mathrm{cotA}tanA+cotA

  2. B

    secA+cosecA\mathrm{secA}+\mathrm{cosecA}secA+cosecA

  3. C

    sinAcosA+1\mathrm{sinAcosA}+1sinAcosA+1

  4. D

    secAcosecA+1\mathrm{secAcosecA}+1secAcosecA+1

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