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The number of values of x in the interval [0,3 π] satisfying the equation 2 sin ^2 x+5 sin x-3=0 is

JEE Main 2006 — Mathematics Trigonometry

2006mcqmedium

The number of values of xxx in the interval [0,3π][0,3 \pi][0,3π] satisfying the equation 2sin⁡2x+5sin⁡x−3=02 \sin ^2 x+5 \sin x-3=02sin2x+5sinx−3=0 is

Official previous-year question

Held on 30 Apr 2006 · Verified 6 Jul 2026.

Options

  1. A

    4

  2. B

    6

  3. C

    1

  4. D

    2

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