sinα+sinβ=−6521 and cosα+cosβ=−6527. Squaring and adding, we get 2+2cos(α−β)=(65)21170⇒cos2(2α−β)=1309⇒cos(2α−β)=130−3(∵2π<2α−β<23π).
JEE Main 2004 — Mathematics Trigonometry
Let α,β be such that π<α−β<3π. If sinα+sinβ=−6521 and cosα+cosβ=−6527, then the value of cos2α−β is
Held on 30 Apr 2004 · Verified 6 Jul 2026.
−1303
1303
656
−656
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