The sequence k,2k,3k,…,1000k has 1000 terms.
The median is 2500k+501k=21001k.
The mean deviation is MD=10001i=1∑1000∣ik−median∣.
For i≤500: deviation = 21001k−ik, giving i=1∑500(21001−i)=125000.
By symmetry, the sum for i≥501 is also 125000.
Thus MD=1000k⋅250000=250k=500, so k=2 and k2=4.