Class midpoints: 6,10,14,18.
Frequencies: 3,λ,4,7. N=14+λ.
Mean μ=14+λ200+10λ.
∑fixi2=3(36)+100λ+4(196)+7(324)=3160+100λ.
Variance: 19=N3160+100λ−μ2.
Let u=14+λ:
19u2=u(1760+100u)−(60+10u)2⇒19u2−560u+3600=0.
u=38560±200, so u=20⇒λ=6.
μ=20260=13. Hence λ+μ=6+13=19.