$\begin{aligned}
& 8+(n-1) 13=320 \
& 13 n=325 \
& n=25 \
& \text { no. of terms }=25
\end{aligned}\begin{aligned}
& \text { mean }=\frac{\sum \mathrm{x}{\mathrm{i}}}{\mathrm{n}}=\frac{8+21+\ldots+320}{25}=\frac{\frac{25}{2}(8+320)}{25} \
& \text { variance } \sigma^2=\frac{\sum \mathrm{x}{\mathrm{i}}^2}{\mathrm{n}}-(\text { mean })^2 \
& =\frac{8^2+21^2+\ldots .+320^2}{13}-(164)^2 \
& =8788
\end{aligned}$